![]() First case is when the we know the size of n and r already, and its the easy one. Heres an example of a recursive function that generates all. For a given string of size n, there will be nk possible strings of length 'length'. Given a string of length n, print all permutation of the given string. Let me first re-write your specification: Print all permutations with repetition of characters. 26.3k 12 12 gold badges 98 98 silver badges 98 98 bronze badges. To generate all permutations of a given string in Java, you can use a recursive approach. Simple recursive solution which will work for you for sure. So, basically, what you do is build incrementally all permutations. This is my code: def splitstring (s, minstrlength 2, rootstring, results ): ''' :param s: word to split, string :param minstrlength: the minimum character for a sub string :param rootstring: leave empty :param results: leave empty :return: nested. Backtracking is a general algorithm 'that incrementally builds candidates to the solutions, and abandons each partial candidate ('backtracks') as soon as it determines that the candidate cannot possibly be completed to a valid solution.'(Wikipedia). When choosing r of them, the permutations are: class String def allpossiblepermutations .map(&:join) end end ruby Share. Write an algorithm that takes an input string like abc, and prints out all possible permutations of the string. My solution allows you to also set a threshold for the minimum size of sub string. Please don't advise a recursive solution, because I want to work through it iteratively first. I'll be glad to clarify my reasoning for it, I know it's not the most efficient, but do bear in mind the fact that I'm only in grade 10 and this is what came to my mind first.Ĭan someone please help me out, or at least hint at what's wrong? If I remove the outermost loop and try to print it, it works for 3 and 4 letter words but not for 5+ letter words. ![]() My solution does just that, but when I try to use 3 or 4 letter words, it gives me repetitions. Printing all permutations of a given string is an example of backtracking problem. The book asks me to do it for the characters 'c','a','r','b','o','n'. One of the questions is to print all permutations of a string. ![]() I'm a high school student of grade 10 trying to work through some problems in a Data Structures and Algorithms book on Java. ![]()
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